Estimation of the formworks’ quantity
In constructional works, it is common practice to pay the technicians responsible for the form- work implementation, based upon the quantity (in m3) of casted concrete. However, the most proper way is to separate those two things therefore, the following pages regard the estimation of the required moulds.
Ground floor
|
Beams – Slabs |
m2 |
||
|
S1: |
3,80 x 5,00 – 4 x 0,40 x 0,10 + 2 x 3,60 x 0,18 |
= |
20,136 |
|
b1,b2: |
2 x 5,00 x 0,50 + 2 x (5,00-2 x 0,40) x 0,32 + + 2 x 4,20 x 0.30 |
= |
10,208 |
|
columns (joints): |
4 x 0,40 x 0,50 + 4 x 0,40 x 0,32 + 4 x 0,10 x 0,32 |
= |
1,440 |
|
Sum |
= |
31,784 |
|
|
Columns: |
|||
|
4 x (0,40 x 0,40 x 2,50) |
= |
16,000 |
|
Basement
|
Beams – Slabs |
m2 |
||
|
S1: |
4,50 x 3,90 – 4 x (0,15 x 0,15) |
= |
17,460 |
|
b1,b2: |
2 x [5,00 x 0,50 +4,20 x 0,32] + 4,20 x 0,25 |
= |
9,788 |
|
b3: |
4,40 x 0,50 + 3,60 x 0,32 + 3,60 x 0,25 |
= |
4,252 |
|
sw5: |
4,40 x 0,50 + 3,60 x 0,32 |
= |
3,352 |
|
internal column sides |
4 x 2 x 0,15 x 0,32) |
= |
0,384 |
|
Sum |
= |
35,236 |
|
|
Columns: |
4 x (0,40 x 0,40 x 2,50) – 2 x (0,25 x 2,50) |
= |
14,750 |
|
Shear wall sw5: |
2 x (3,60 x 2,50) |
= |
18,000 |
|
Sum |
= |
32,750 |
Foundation
|
m2 |
|||
|
Footings F3,4,5: |
0,50 x [5,00 + 2 x 1,00 + 0,30 x 2] |
= |
5,85 |
|
Cb1,2: |
2 x [0,70 x0,10 + 4,30 x 0,60 + 0,30 x 0,30] 2 x [0,30 x0,10 + 3,60 x 0,60 + 0,30 x 0,30] |
= |
10,04 |
|
Sf4: |
(3,80 + 4,40) x 0,30 + (3,60 + 4,40) x 0,30 |
= |
4,86 |
|
Columns: |
2 x 2 [0,10 x 0,30 +0,10 x 0,10] + +(4,40+3,60 ) x 0,10 |
= |
0,96 |
|
Sum |
= |
21,71 |
|
