Structural System – II
Estimation
Bar Bending Schedule
Bar Bending Schedule
| Serial # | Bar Designation | Number of Bars |
Length of one Bar |
Dia of bar |
Weight of Steel Required |
Shape of Bar |
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| #10 | #13 | #15 | #19 | #25 | ||||||
|
1 |
M-1 |
#25 |  |
 |
||||||
|
2 |
S-1 |
#10 |  |
 |
||||||
|
3 |
H-1 |
#15 |  |
 |
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Total weight of steel = 1.05Σ , 5% increase, for wastage during cutting and bending
Bar Bending Schedule (contd…)
Additional Length = 0.414 h
Total Length = L + 0.414h
2h = 1.414h
1.414h – 1h = 0.414 h
Bar Bending Schedule (contd…)
Bar Bending Schedule (contd…)
M-1 = 4000 + 2 x 228 – 2 x 40 + 2 x (18 x 20)
= 5096
h = 375 – 2 x 40 – 2 x 10 – 2 (15/2) = 260
M-2 = 4000 + 2 x 228 – 2 x 40 + (0.414 x 260) x 2
= 5091
H-1 = 4000 + 2 x 228 – 2 x 40
= 4376
Bar Bending Schedule (contd…)
Shear stirrups
Number of Bars = 4000 /180 +1 = 24
a = 375 – 2 x 40 – 10 = 285 mm
b = 228– 2 x 40 – 10 =138 mm b
Total length of S-1 = 2 (138 + 285 + (4×10 + 75)) = 1076 mm
Bar Bending Schedule
Concluded
