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12)T & L Beams

Design Principles of Concrete Structures

Lecture 12

T & L Beams

T & L Beams

T & L Beams

  • With the exception of pre-cast systems, reinforced concrete floors, roofs, decks, etc., are almost always kept monolith.
  • Beam stirrups and bent bars extend up into the slab.


  • It is evident, therefore, that a part of the slab will act with the upper part of the beam to resist longitudinal compression.
  • The slab forms the beam flange, while a part of the beam projecting below of the slab forms is called the “web” or “stem”.

T & L Beams (contd…)


b = Effective width

bw = width of web/rib/stem

hf = Thickness of flange

Effective With of T & L Beams

T-Beams

Effective width will be minimum of the following:

1. L/4

2. 16hf + bw

3. bw + ½ x (clear spacing of beams (Si) on both sides) = c/c spacing for beams at regular interval

Effective With of T & L Beams

L-Beams

Effective width will be minimum of the following:

  1. L/12
  2. 6hf + bw
  3. bw + Si/2 on one side

Note: Only above discussion is different for isolated (pre- cast) T or L beam. Other discussion is same (analysis and design formula).


Flexural Behavior (contd…)

Case-II: Flange is in Compression and N.A. lies with in Flange

beam can be designed as a rectangular beam hf of total width “b” and d effective depth “d”.


Flexural Behavior (contd…)

Case-III: Flange is in Compression and N.A. lies out of the Flange

Beam has to be designed as a T-Beam.

Separate expressions are to be developed for analysis and design.

b



Flexural Behavior (contd…)

It is convenient to divide total tensile steel into two parts. The first part, Asf represents the steel area which, when stressed to fy, is required to balance the longitudinal compressive force in the overhanging portions of the flange that are stressed uniformly at 0.85fc’.

The remaining steel area A– Asf, at a stress fy, is balanced by the compression in the rectangular portion web above the N.A.

T= Asf fs

T= Aswfs= (AsAsf)fs

Flexural Behavior (contd…)

Majority of T and L beams are under-reinforced (tension controlled). Because of the large compressive concrete area provided by the flange.

For longitudinal equilibrium

S= 0

T= CfT= Cw


Flexural Behavior (contd…)

Flexural Capacity

From Compression Side

M= Mnf + Mnw


Flexural Behavior (contd…)

Flexural Capacity

From Tension Side

M= Mnf + Mnw


Tension Controlled Failure of T-Beam


Tension Controlled Failure of T-Beam (contd…)

For longitudinal equilibrium

= C + Cf

= C + Tf

= 0.85f‘ b + A sf y



Concluded

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