Learn

6)Under Reinforced & Over Reinforced

Design Principles of Concrete Structures

Lecture 6

Under Reinforced & Over Reinforced

(Derivation)

Under-Reinforced Failure

Stage-I, Un-cracked Section

N.A. position is fixed, means “la” remains constant. Only “T” and “Cc” increase with the increase of load

Stage-II, Cracked Section

When section cracks, N.A. moves towards compression face means “la” increases. “T” and “Cc” also increase.

a/2 Cc




Internal Force Diagram

Under-Reinforced Failure (contd…)

Stage-III, Yielding in Steel Occur

T = As fy remains constant and Cc also remains constant. “la” increases as the

N.A. moves towards compression face because cracking continues.

Failure initiates by the yielding of steel but final failure is still by crushing of concret.


Und er-Reinforced Failure( contd…).

Derivation for p

Design Moment Capacity

For tension controlled sectio<D 0..9

And


UnderReinforced Failure (contd.,.. “‘ ,. )

Put value  of
  from (1to 
(2)

 


For econon1ical Design



By Simplifaication



 



As we know, Reinforcement Ratio is,



So,

Area of Steel Awill be

𝐴𝑠 = 𝜌 × 𝑏𝑑

Trial Method for the determination of “As


Trial # 1, Assume some value of “a” e.g. d/3 or d/4 or any other reasonable value, and put in (C) to get “As”

Trial # 2, Put the calculated value of “As” in

  1. to get “a”. Put this “a” value in (C) to get

    “As”

    Keep on doing the trials unless “As” from a specific trial becomes equal to the “As” calculated from previous trial.

    THIS VALUE OF AS WILL BE THE FINAL ANSWER.

    Is The Section is Under-Reinforced or NOT?

    1. Calculate ρ and if it is less than ρmax, section is under reinforced
    2. Using “a” and “d” calculate εt if it is ≥ 0.005, section is under-reinforced (tension controlled)
    3. If section is over-reinforced than in the following equation –ve term will appear in the under-root.


Over-Reinforced Failure

Stage-I, Un-cracked Section

Stage-II, Cracked Section

These two stages are same as in under-reinforced section.

Stage-III, Concrete reaches strain of

0.003 but steel not yielding

We never prefer to design a beam as over- reinforced (compression controlled) as it will show sudden failure.

Φ = 0.65  εs < εy fs<fy

Stage-III, Concrete reaches strain of 0.0103 but steel not yielding (co11td )




StageIII, Concretreaches strain o0.003 busteel noyielding(contd…)

Putting value of  fs from (iv to (ii)



Summary


Concluded

learn
We will be happy to hear your thoughts

Leave a reply

Share knowledge
Learn
Logo
Enable registration in settings - general