Quantities surveying-Cost estimation
The following paragraphs refer to the quantities and cost estimation of the building shown at the next fig- ure.
It is comprised of a ground floor and a basement (with one shear wall) while its strip foundation is combined with spread footings tied together by connecting beams. The following paragraphs present the detailed quantities estimates of materials like concrete, form- works, spacers, reinforcements, the reinforcement schedules’ optimization as well as the total quantity and cost estimation of the structural frame.
A simple building with a ground floor and a basement
<project: Estimation10>
Estimation of the concrete’s quantity
Ground floor
Beams – Slabs
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S1: 4,40 x 5,00 x 0,18 |
= |
3,96 |
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� |
b1,b2: 2 x [(5,00-2 x 0,40) x 0,30 x 0,32] |
= |
0,81 |
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C1,2,3,4 (part of the joint area): 4 x (0,40 x 0,40 x 0,32)
Sum |
=
= |
0,20
4,97 m3 |
Columns
C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3
Basement
Beams – Slabs
S1: 4,40 x 5,00 x 0,18 = 3,96
� b1,b2: 2 x [(5,00-2 x 0,40) x 0,25 x 0,32] = 0,67
b3,sw5: 2 x [(4,40-2 x 0,40) x 0,25 x 0,32] = 0,58
C1,2,3,4 (part of the joint area): 4 x (0,40 x 0,32) = 0,20 Sum = 5,41 m3
Columns
� C1,2,3,4: 4 x (0,40 x 0,40 x 2,50) = 1,60 m3
SW5: 3,60 x 0,25 x 2,50 = 2,25
Sum = 3,85 m3
Foundation
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Footings f3,4,5: 2 x (1,00 x 1,00 x 0,50) +3,00 x 0,85 x 0,50 |
= |
2,275 |
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� CB1,2: |
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2 x (3,60 x 0,30 x 0,60) + (2 x 0,30 x 0,10 x 0,30) + |
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+ 2 x (0,30 x 0,30 x 0,30) |
= |
1,368 |
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SF: 4,40 x 1,00 x 0,30 + 4,40 x 0,30 x 0,30 |
= |
1,716 |
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0,60 m, compared to the footings’ depth which is 0,50m): |
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4 x (0,40 x 0,40 x 0,10) + 3,60 x 0,25 x 0,10 |
= |
0,154 |
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(2 x 0,10 x 0,10 x 0,20 = 0,004) Sum |
= |
5,51 m3 |
